Q. No.The voltage \(V_{AB}=20~\text{V}\) at its peak value, and is sinusoidal in time. The current \(i\) (in amperes), when plotted as a function of time, is given by:
(consider the diodes as ideal.)
1.
2.
3.
4.
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| 1. | \(V_o=V_i+E\) |
| 2. | \(V_o=V_i-E\) |
| 3. | \(V_o=V_i,\) only when \(V_i>E\) |
| 4. | \(V_o=V_i,\) only when \(V_i<E\) |
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1. \(V_A>V_B+V_0\)
2. \(V_A<V_B+V_0\)
3. \(V_A>V_B-V_0\)
4. \(V_A<V_B-V_0\)
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| 1. | no current flows in the circuit |
| 2. | current flows anticlockwise |
| 3. | current flows clockwise |
| 4. | current only flows through \(D_2\) and not through \(D_1\) |
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1. zero2. \(4~\text{mA}\)
3. \(2.5~\text{mA}\)
4. \(0.8~\text{A}\)
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1. zero2. \(20\) mA
3. \(40\) mA
4. \(20\sqrt2\) mA
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For the above circuit, the applied voltage \(V(t)\) is periodic and linear, and is shown by the waveform below:
The current flowing through \(R_2\) varies as:
| 1. |  |
2. |  |
| 3. |  |
4. |  |
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1. AND
2. OR
3. XOR
4. none of the above
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1. AND gate
2. OR gate
3. XOR gate
4. null gate (always zero)
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